Hi,
this...
> for (i in length(asc.files[i])) {
...only works if the variable i existed previously, and it seems that
its value happened to be 1 in your case. It then counts from
length(asc.files[i]) to length(asc.files[i]); asc.files[i] is a vector
of length one (because i is 1), so the for
Hi Alex-
Thanks for the response, which helped me get a step closer to what I want.
Now that I have removed the extensions from the files as you suggest, I am
able to process one file, but am not able to process an entire directory of
files. Upon running a loop over all files in the directory, it
Dear Virgilio,
thanks for the link. I'll have a look at it immediately.
Kind regards,
Michel
2009/3/1 Virgilio Gomez Rubio
> Michel,
>
> In addition to the comments that have already been made, there is an
> example of overlying results (IDW, but kernel estimation can be done in
> a similar w
Dear Barry,
The Google Maps API gives me the bounds by calling the getBounds() function.
This gives me the following bounds for example:
((51.888464736976516, 4.457187652587891), (51.92023802576216,
4.543018341064453))
I've used the following R code to generate the KDE surface:
library(Cairo)
l
Hi Tim,
the rsaga.esri.wrapper currently expects the in.* and out.* arguments
(with the ASCII/float ESRI grids) to have NO file extension - the file
extension to be used for all ESRI grids can be given by the
esri.extension argument; it currently defaults to ".asc" when
format="ascii" and to
Hi all,
Is anyone aware of any code for performing topologically consistent
polygon thinning/simplification/generalisation in R?
Hadley
--
http://had.co.nz/
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Michel,
In addition to the comments that have already been made, there is an
example of overlying results (IDW, but kernel estimation can be done in
a similar way) here:
http://www.asdar-book.org/book/die.R
Look at chunks 41 to 44.
Hope this helps.
Virgilio
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