>> Look at manipulating the IFS variable; you can do wondrous things with
that.
Yep, I've thought about it, but that's all so far.
>> Next, we get into opening and using file descriptors...
All in good time. :)
bd
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>> See my other replies for more thoughts on this, but it actually has to be
>> "s/$//g", and must use "s rather than 's.
Whoops! My bad. :) Both of these work...
's/\\$//g' # single quotes
"s/$//g"# double quotes
Thanks to Matthew for catching my goof
>> That's making the big assumption that wrong sort of quotes is your
problem.
>> If not then umm.. err.. *shurg* ... Did i meantion in worked for me? ;)
Yep, you nailed it. Thanks for taking time to post the echo examples!
bd
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On Fri, Jan 26, 2001 at 09:41:30AM -0800, Brad Doster wrote:
> IOW, I can treat the list as space or line delimited. Using var3=`echo
> "$var1\n$var2"` eliminates the ability to treat it as a space delimilted
> list as 'echo $var3' and 'echo "$var3"' both produce 'a\nb'.
Well, in one sense--in a
>> Now what you should do is store the \n's in var3 like:
>> var3=`echo "$var1\n$var2"`
>> after which:
>> echo -e $var3
>> would give the desired output
Yep, that works too. But :), var3=`echo -e "$var1\n$var2"` seems to be a
bit more flexible in that 'echo $var3' produces...
a b
...a
>> varlist=`echo "$varlist" | sed 's/\\$//'`
See my other replies for more thoughts on this, but it actually has to be
"s/$//g", and must use "s rather than 's.
Thanks for your input!
bd
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Brad Doster
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-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]On Behalf Of Luke C Gavel
Sent: Friday, January 26, 2001 2:18 AM
To: [EMAIL PROTECTED]
Subject: RE: Bash Script Questions
On Fri, 26 Jan 2001 at 8:34am (-0800), Brad Doster wrote:
> >> Ahhh.. we need another \ - one to protect $ from sed and
> >> another to protect the first \ from the backticks.
>
> >>varlist=`echo "$varlist" | sed 's/\\$//g'`
>
> Apparently that's still not enough. I think '\\$' parses to '\$
-Original Message-
From: Matthew Melvin [mailto:[EMAIL PROTECTED]]
Sent: Thursday, January 25, 2001 9:57 PM
To: Brad Doster
Cc: [EMAIL PROTECTED]
Subject: RE: Bash Script Questions
On Thu, 25 Jan 2001 at 7:56pm (-0800), Brad Doster wrote:
> Hi Matthew,
>
> Perhaps what I'm do
>> var3=`echo -e "$var1\n$var2"`
>>...does the trick.
It's the -e option in echo that's doing this, it allows the \n to be
read and used as a new line. e.g. echo -e "$var1\n$var2" should
read:
a
b
but echo var3 after above would still give:
a b
Now what you should do is store the \n's in v
probably a bit late with this but;
> > varlist=`echo "$varlist" | sed 's/$//'`
>
varlist=`echo "$varlist" | sed 's/\\$//'`
> > 2) Given two variables, say var1="a" and var2="b", I want to create var3
> > such that it is "ab", i.e 'echo "$var3"' produces:
> >
> > a
> > b
> >
>
You w
On Thu, 25 Jan 2001, Brad Doster wrote:
> But why? Why doesn't good ol' '\$' work right out of the
> box?
Because the '$' is used in a special by the shell (script) and
sed too. sed uses the '$' to anchor a search pattern from the
end of a line, and, of course the script uses it to expand
vari
On Thu, 25 Jan 2001 at 7:56pm (-0800), Brad Doster wrote:
> Hi Matthew,
>
> Perhaps what I'm doing in the '$' case needs a bit more explanation. The
> following is a script segment that gleans variable names from the script in
> which it is run:
>
> for varname in case select until while
>> varlist=`echo "$varlist" | sed -e "s/$//g"
Yep, that did it! But, what did it do? Or, where can I find info that will
help me make sense of it? FWIW, it looks to me like it's searching for
'\\$' (???). Oooh it is! But the '\\$' gets reduced to '\$' which then
works as desired.
Hi Matthew,
Perhaps what I'm doing in the '$' case needs a bit more explanation. The
following is a script segment that gleans variable names from the script in
which it is run:
for varname in case select until while ; do
varlist=`cat "$0" | grep "^[]*$varname " | se
On Thu, 25 Jan 2001 at 10:21am (-0800), Brad Doster wrote:
> 1) I have a variable with a list of variable names as its content, e.g.
> 'varlist=$var1 $var2 $var3'. I want to manipulate $varlist such that it
> ='var1 var2 var3', i.e get rid of the '$'s in front of each variable name.
> A 'sed' ex
On Thu, Jan 25, 2001 at 10:21:39AM -0800, Brad Doster wrote:
> 1) I have a variable with a list of variable names as its content, e.g.
> 'varlist=$var1 $var2 $var3'. I want to manipulate $varlist such that it
> ='var1 var2 var3', i.e get rid of the '$'s in front of each variable name.
> A 'sed' e
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