Rafael Ubaldo wrote in post #1016660:
It matches because it's true. The expressions states any number of
digits before the end of line. It does not state exclusively digits.
Wrong. The regex says:
1) match start of line(or just after a newline)
2) match a digit 0 or more times
3) match just
On Aug 14, 7:29 pm, Misha Ognev li...@ruby-forum.com wrote:
Hi! This problem(in model):
validates :some_digits_collection, :presence = true, :format = { :with
= /^\d*$/, :message = Must contain only digits! }
So, :some_digits_collection must match only digits. But when I puts
123f(for
Agreed.
@OP: You should try this instead:
http://edgeguides.rubyonrails.org/active_record_validations_callbacks.html#numericality
On Mon, Aug 15, 2011 at 2:41 PM, Frederick Cheung
frederick.che...@gmail.com wrote:
On Aug 14, 7:29 pm, Misha Ognev li...@ruby-forum.com wrote:
Hi! This
^[1-9]\d*$
Walter, thanks for this.
Is this column an integer column? If so, then I seem to recall that at
the point that validations run rails has already converted the
argument to an integer, i.e. it will have converted your 123f to 123
and so your validation passes.
Fred, how I can fix
Dheeraj Kumar, it works, thanks!
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Perhaps the input value is being cast to
an integer for storage, and so the trailing letters are being stripped
out.
This is one simple way to check this: puts f123 to field.
f123.to_i = 0
123f.to_i = 123
But in Rails validation, f123 is validates too.
Michael
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Posted via
But 0 passes this regex -- it's one digit. If you wanted to ensure
that you had n or more digits, you would use a regex like this:
^\d{2,}$
to match two or more digits.
Or, you could check to see if the first digit was larger than a 0 if
that first digit cannot ever be 0:
^[1-9]\d*$
7 matches
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