Thanks~~
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On 15/02/2012 18:36, shawn wrote:
> yeah, I have thought about it. But if I use function, I have to write three
> for loops. like:
>
> /*function Boolean findSubject(Request request) {
>
> Pointer sPointer = request.getSubjectPath();
> Pointer aPointer = request.getAuthorTable();
>
Thank you~
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On 15/02/2012, shawn wrote:
> I found someone idea. It's kind of like split array.
> when
> Request( $sPath : getSubjectPath() ) // get two dimensional array
> then
> for( int i = 0; i < $sPath.length; i++ ) {
>
> insert( $sPath[i]);
>
> }
> But I don't know
I found someone idea. It's kind of like split array.
when
Request( $sPath : getSubjectPath() ) // get two dimensional array
then
for( int i = 0; i < $sPath.length; i++ ) {
insert( $sPath[i]);
}
But I don't know how to find the facts
yeah, I have thought about it. But if I use function, I have to write three
for loops. like:
/*function Boolean findSubject(Request request) {
Pointer sPointer = request.getSubjectPath();
Pointer aPointer = request.getAuthorTable();
for( int i = 0; i < p.length; i++ ) {
Consider writing a DRL function that does the test and call it in an inline
eval().
-W
On 15 February 2012 18:26, shawn wrote:
> Hi,
> I meet a problem to find an element in an array.
> First, I have a 2 dimensional array and a 1 dimensional array.
> I need to compare whether the element in 2 di
Hi,
I meet a problem to find an element in an array.
First, I have a 2 dimensional array and a 1 dimensional array.
I need to compare whether the element in 2 dimensional array is as same as 1
dimensional array.
How to solve it?
Like:
In Java - int [][] A; int [] B;
how to iterate array A and array
