Hi,
integrate(sin(x)*exp(I*x),x,-pi,0) returns 3/2*I*pi instead of 1/2*I*pi
Is this a known issue? I couldn't find it reported elsewhere.
Best regards,
Jeremie Knuesel
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Hi,
Indeed, this seems a bug in Sage.
Note that both SymPy and Giac return the correct answer:
sage: integrate(sin(x)*exp(I*x), x, -pi, 0)
3/2*I*pi
sage: integrate(sin(x)*exp(I*x), x, -pi, 0, algorithm='sympy')
1/2*I*pi
sage: integrate(sin(x)*exp(I*x), x, -pi, 0, algorithm='giac')
1/2*I*pi
Eric
Hi
Reduction of rational functions seems not to work in specific cases.
In the following output,
===
sage: R.=QQ[]
sage: (2*t+2)/(2*t)
(2*t + 2)/(2*t)
sage: (2*t+2)/(2)
t + 1
sage: (2*t^2+2*t)/(2*t)
t + 1
===
2 is not reduced in the first calculation.
SageMath ve
The representation is indeed not canonical but the object compare coherently
sage: R.=QQ[]
sage: (2*t+2)/(2*t)
(2*t + 2)/(2*t)
sage: (2*t+2)/(2*t) == (t+1)/t
True
The reason is that 2 is a unit in QQ. You can compare with
sage: R.=ZZ[]
sage: (2*t+2)/(2*t)
(t + 1)/t
It would be nice to have bet
On Sunday, April 15, 2018 at 9:27:40 PM UTC+1, vdelecroix wrote:
>
> The representation is indeed not canonical but the object compare
> coherently
>
> sage: R.=QQ[]
> sage: (2*t+2)/(2*t)
> (2*t + 2)/(2*t)
> sage: (2*t+2)/(2*t) == (t+1)/t
> True
>
> The reason is that 2 is a unit in QQ. Yo
On Sunday, April 15, 2018 at 3:53:08 PM UTC-7, Dima Pasechnik wrote:
>
>
> It would be nice to have better simplification rules for QQ (and more
>> generally fraction fields).
>>
>
> I suppose it's only OK to have as an option, as in general computing such
> a canonical
> form would be slow, no?
I'm so sorry I re-posted this error. It was the same original compile
problem. Instead of using the normal compilers, it was pointing to the
MOOSE compilers. So, commenting out the links to those compilers in .bashrc
let the kernel connect just fine. The basic jist is, if you have different
or
Not Sage, it's Maxima:
(%i2) integrate(sin(x)*exp(%i*x),x,-%pi,0);
log(- 1)
(%o2) + %i %pi
2
On Sunday, April 15, 2018 at 6:44:23 PM UTC+2, Eric Gourgoulhon wrote:
>
> Hi,
>
> Indeed, this s
FriCAS also would get it right, except that there is a bug in the
interface, see https://trac.sagemath.org/ticket/25174
If someone can give me a hint on how to send %i instead of I for the
imaginary unit to fricas, I'll fix it...
(1) -> integrate(sin(x)*exp(%i*x),x=-%pi..0)
%i %pi
(
