[sage-devel] Re: Block TermOrder equality is broken

On 2018-03-15, Simon King wrote: >sage: R = PolynomialRing(QQ, 6, 'x', order="lex(1),degrevlex(5)") >sage: S = R.change_ring(order="lex(2),degrevlex(4)") >sage: R is S >True > > So, indeed it is a bug. ... which is being dealt with at

[sage-devel] Re: Block TermOrder equality is broken

Hi Kwankyu, On 2018-03-15, Kwankyu Lee wrote: >> sage: R = PolynomialRing(QQ, 6, 'x', order="lex(1),lex(5)") >> sage: S = R.change_ring(order="lex(2),lex(4)") >> sage: S.term_order() >> >> Block term order with blocks: >> (Lexicographic term order of length 1, >>

[sage-devel] Re: Block TermOrder equality is broken

On Thursday, March 15, 2018 at 9:59:44 AM UTC+9, Nils Bruin wrote: > > On Thursday, March 15, 2018 at 12:44:39 AM UTC, Kwankyu Lee wrote: >> >> Hi, >> >> Which part of the output you consider wrong? Would you elaborate on the >> "incorrect behaviour"? >> >> > sage: R = PolynomialRing(QQ, 6,

[sage-devel] Re: Block TermOrder equality is broken

On Thursday, March 15, 2018 at 12:44:39 AM UTC, Kwankyu Lee wrote: > > Hi, > > Which part of the output you consider wrong? Would you elaborate on the > "incorrect behaviour"? > > sage: R = PolynomialRing(QQ, 6, 'x', order="lex(1),lex(5)") sage: S = R.change_ring(order="lex(2),lex(4)") sage:

[sage-devel] Re: Block TermOrder equality is broken

Hi, Which part of the output you consider wrong? Would you elaborate on the "incorrect behaviour"? Kwankyu -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to