Thanks John!
On Jul 10, 4:04 am, John Cremona wrote:
> I forwarded the whole thread to sage-nt (which I see you have joined,
> Lenny) and changed the title there,
>
> John
>
> 2009/7/10 Leonard Foret :
>
>
>
> > Is possible to change the name of this discussion? I made a mistake,
> > the lattic
I forwarded the whole thread to sage-nt (which I see you have joined,
Lenny) and changed the title there,
John
2009/7/10 Leonard Foret :
>
> Is possible to change the name of this discussion? I made a mistake,
> the lattice is in SL(2, CC) and not SL(2, Z[i]).
>
> Lenny
>
> On Jul 9, 8:02 pm, L
Is possible to change the name of this discussion? I made a mistake,
the lattice is in SL(2, CC) and not SL(2, Z[i]).
Lenny
On Jul 9, 8:02 pm, Leonard Foret wrote:
> Excellent, will do. That was my original idea, but I was thrown off a
> bit by the request for membership. Anyway, the request
Excellent, will do. That was my original idea, but I was thrown off a
bit by the request for membership. Anyway, the request went through
so I'll re-post this there.
Thanks,
Lenny
On Jul 9, 4:24 am, John Cremona wrote:
> It's clear what your algebra is: over the base field K=Q(i) it's the
>
It's clear what your algebra is: over the base field K=Q(i) it's the
quaternion algebra with parameters 2,5.
I think that sage-nt would be a better forum for this than sage-devel.
Ask to join (at http://groups.google.co.uk/group/sage-nt).
John
2009/7/9 Leonard Foret :
>
> The problem is about
The problem is about finding co-compact lattices in SL(2, C) by using
quaternion algebras.
The example we are working out now is based on the Quaternion algebra
over Q(i) defined by the quadratic extension Q(i)[X]/(X^2 - 2) and
additional (non-commutative) relation s^2 = 5.
We need the algebra
On Sat, Jul 4, 2009 at 8:39 PM, Leonard Foret wrote:
>
> Hello all,
>
> This is my first time in sage-devel. I have a project with a
> professor til the end of August to construct cocompact/uniform
> lattices on SL2(Z[i]) basically by quaternion algebras.
What is a "lattice on SL2(Z[i])"?
> I
