On Fri, Apr 24, 2009 at 9:03 AM, Robert Miller rlmills...@gmail.com wrote:
sage: x = polygen(ZZ)
sage: f = 2*x^2
sage: f.mod(2)==0
False
You should do f.mod? and read the docstring, which says:
Return a representative for self modulo the ideal I (or the ideal
generated by the elements of
Worse still:
sage: x = polygen(QQ)
sage: h = 4*x
sage: h%3
0
--~--~-~--~~~---~--~~
To post to this group, send email to sage-devel@googlegroups.com
To unsubscribe from this group, send email to
sage-devel-unsubscr...@googlegroups.com
For more options, visit
Worse still:
sage: x = polygen(QQ)
sage: h = 4*x
sage: h%3
0
Over QQ[x], isn't 4*x = 3 * (4/3*x) ? Over ZZ, it's fine:
sage: x = polygen(ZZ)
sage: h = 4*x
sage: h%3
x
-cc
--~--~-~--~~~---~--~~
To post to this group, send email to
Yeah, I should have mentioned that my point was that maybe h%3 should
raise an error over QQ.
On Apr 24, 11:00 am, Craig Citro craigci...@gmail.com wrote:
Worse still:
sage: x = polygen(QQ)
sage: h = 4*x
sage: h%3
0
Over QQ[x], isn't 4*x = 3 * (4/3*x) ? Over ZZ, it's fine:
sage: x
On Fri, Apr 24, 2009 at 11:53 AM, Robert Miller rlmills...@gmail.com wrote:
Yeah, I should have mentioned that my point was that maybe h%3 should
raise an error over QQ.
Over QQ, the number 3 generates the unit ideal, so everything is 0
modulo it :-).
William
On Apr 24, 11:00 am, Craig
