Thanks. Hopefully some of the math will start coming back as I go
through this. I'm glad I didn't spend an hour looking for the
'conversion'.
--~--~-~--~~~---~--~~
To post to this group, send email to sage-support@googlegroups.com
To unsubscribe from this group,
On Thu, Aug 20, 2009 at 4:58 PM, Hermit wrote:
>
> Sorry but I've spent over an hour on google and not found this. I've
> had calculus but haven't used it in years. I decided to do some
> brushing up and learn sage at the same time.
>
> I have the number -0.6167. If I want degree representatio
On Aug 20, 2009, at 7:58 PM, Hermit wrote:
>
> Sorry but I've spent over an hour on google and not found this. I've
> had calculus but haven't used it in years. I decided to do some
> brushing up and learn sage at the same time.
>
> I have the number -0.6167. If I want degree representation o
Sorry but I've spent over an hour on google and not found this. I've
had calculus but haven't used it in years. I decided to do some
brushing up and learn sage at the same time.
I have the number -0.6167. If I want degree representation on my old
HP48 I use acos and get 128(degrees) In sage
Hi all,
I would like to inform you about new packages - FuncDesigner and
DerApproximator. They have been extracted from OpenOpt into standalone
Python modules.
FuncDesigner is a convenient tool for building functions and getting
their derivatives via Automatic differentiation (http://openopt.org/
Perhaps you could convert this into a system of linear equations then
use the solve command?
On Thu, Aug 20, 2009 at 2:39 PM, Santanu
Sarkar wrote:
> Hi,
> How can I find the solution x1,...,z3 in SAGE where
> A= [x1,x2,x3,
> y1,y2,y3,
> z1,z2,z3] is a (3,3) matrix which satisf
On Thu, Aug 20, 2009 at 11:39 AM, Santanu
Sarkar wrote:
> Hi,
> How can I find the solution x1,...,z3 in SAGE where
> A= [x1,x2,x3,
> y1,y2,y3,
> z1,z2,z3] is a (3,3) matrix which satisfy AB=C
> where B=[1,2
> 3,4,
> 5,6] a (3,2) matrix and
> C=
Hi,
How can I find the solution x1,...,z3 in SAGE where
A= [x1,x2,x3,
y1,y2,y3,
z1,z2,z3] is a (3,3) matrix which satisfy AB=C
where B=[1,2
3,4,
5,6] a (3,2) matrix and
C=[0,0,
1,0,
0,2] another (3,2) matrix ?
--~--~-~--~-
On Thu, Aug 20, 2009 at 9:02 AM, felix wrote:
>
> Hi,
>
> this should have happened to other people, but I can't find some other
> post on this one.
I wonder if there is almost nobody using Sage who also uses weave?
I've never used weave, and we use it nowhere in the Sage codebase.
As a result of
Hi,
this should have happened to other people, but I can't find some other
post on this one. I'm not sure which update exactly caused the bug,
since I didn't use weave since Sage 3.something. All I can say is,
that weave doesn't work at all in Sage 4.1 and 4.11 (64 bit) under Mac
OS X 10.5.8 on m
On Aug 20, 4:28 am, Jason Grout wrote:
> Robert Bradshaw wrote:
>
> > It's just syntactic sugar.
>
> To see what Sage transforms something like this into, you can use the
> preparse function:
>
> sage: preparse('f(y,z)=y^2+z')
> '__tmp__=var("y,z"); f = symbolic_expression(y**Integer(2)+z).functi
Hi:
I am trying to "define" a variable to be an element of GF(2). In
particular, suppose that I create GF(2^4) the following way:
K=GF(2)
S. = K['x']
QR=S.quotient(1+x+x^4,'a')
a=FR.gen()
Now I am trying to compute the following:
(gamma0 + gamma1*a + gamma2*a^2 + gamma3*a^3)*(beta0 + beta1*a +
12 matches
Mail list logo
