On 2/4/12 4:32 PM, Dana Ernst wrote:
Do you know what the worksheet timeout is set to in your server (log in as the
administrator, go to the Notebook settings page, and look at the Idle timeout)?
It is currently set at 120 seconds. Is there any danger in making that number
1000 or whatever?
On Feb 4, 2012, at 5:48 PM, Jason Grout wrote:
> There's no problem with setting it to 1000 or whatever (I'd probably set it
> to more than that, like 3600, which would be an hour).
>
> My guess is that will solve the problem.
Thanks! My fingers are crossed. I appreciate the help.
Dana
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On 2/4/12 4:32 PM, Dana Ernst wrote:
On Feb 4, 2012, at 5:25 PM, Jason Grout wrote:
Possibly because you are running 4.7, and maybe it happened a lot in 4.7. When
you are editing, how often are you evaluating cells?
Not very often because I'm usually writing directions for my students.
Do
On Feb 4, 2012, at 5:25 PM, Jason Grout wrote:
> Possibly because you are running 4.7, and maybe it happened a lot in 4.7.
> When you are editing, how often are you evaluating cells?
Not very often because I'm usually writing directions for my students.
> Do you know what the worksheet timeo
On 2/4/12 4:00 PM, D.C. Ernst wrote:
I just finished a worksheet for my linear algebra class and while
working on it I had to start over 5 times because I was nailed with the
rearranging text and output bug. I created the worksheet on my school's
notebook server, which is running Sage 4.7. Each t
I just finished a worksheet for my linear algebra class and while working
on it I had to start over 5 times because I was nailed with the rearranging
text and output bug. I created the worksheet on my school's notebook
server, which is running Sage 4.7. Each time here is what happened. I
wou
This is brilliant, thanks!
Vince
On Friday, 3 February 2012, Ivan Andrus wrote:
> Defining it as
> sage: BB=lambda(c):
factorial(c-1)*(mu/(B*mu+1))^2*sum(((c-1/(B*mu+1))^i)/factorial(i),i,0,c-1)
> sage: BB(1)
> mu^2/(B*mu + 1)^2
> gives the evaluated sum. In other words it's a function which re
This is brilliant, thanks!
Vince
On Friday, 3 February 2012, Ivan Andrus wrote:
> Defining it as
> sage: BB=lambda(c):
factorial(c-1)*(mu/(B*mu+1))^2*sum(((c-1/(B*mu+1))^i)/factorial(i),i,0,c-1)
> sage: BB(1)
> mu^2/(B*mu + 1)^2
> gives the evaluated sum. In other words it's a function which re
