Hi Saul,
On 2014-01-23, Saul Schleimer saul...@gmail.com wrote:
It seems to me that this violates the principle of least surprise: if I
have a unit in a ring, and I invert it, I can reasonably expect answer to
be a unit, in that ring...
Yes and no.
If you have an integral domain, you can
Hi Simon -
Nice to hear from you. This discussion of morphisms is pretty
convincing. I tried it out, but I think I am doing something wrong.
sage: Id = matrix([[1,0],[0,1]])
sage: type(Id)
type 'sage.matrix.matrix_integer_dense.Matrix_integer_dense'
sage: A = Mat.get_action(Mat,
Dear all -
Here is a much lighter way make my problem go away.
Suppose that A is an m by n matrix (number of rows by number of columns).
A = matrix(ZZ, [[-6, -26, -82], [0, 4, 3], [1, 0, 7], [0, 2, 5], [2, 10,
30]])
sage: type(A)
type 'sage.matrix.matrix_integer_dense.Matrix_integer_dense'
Hi Saul,
On 2014-01-24, Saul Schleimer saul...@gmail.com wrote:
Nice to hear from you. This discussion of morphisms is pretty
convincing. I tried it out, but I think I am doing something wrong.
...
sage: A = Mat.get_action(Mat, operator.inv); A
sage: A.codomain()
On 01/23/2014 02:04 AM, kcrisman wrote:
However, there are lots and lots of things on that spreadsheet (I
thought it was no longer operational, but I guess old Sage installations
still go there ... including sagenb.org)
The google doc should still be operational for now. The switch to
