How can I find numerical root for the system of equations?
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On Tuesday, 5 May 2015 20:25:46 UTC+1, Paul Royik wrote:
I meant without discontinuous functions.
What is the general approach even in numerical solving of school
functions on the interval?
on the interval it is the bisection method and its versions
Hello,
I am trying to obtain the explicit expression for the solution od an ODE,
my code is
var('k')
y= function('y',x)
h=desolve(diff(y,x) - k*y*(1-y),y, ivar=x)
h
I would like to isolate y(x) = ... (with the computer, of course)
I played around with h.lhs() and h.rhs(), but did not get the
On Tue, May 5, 2015 at 12:58 PM, Jotace jotacebu...@gmail.com wrote:
Hello,
I am trying to obtain the explicit expression for the solution od an ODE, my
code is
var('k')
y= function('y',x)
h=desolve(diff(y,x) - k*y*(1-y),y, ivar=x)
h
I would like to isolate y(x) = ... (with the computer,
I meant without discontinuous functions.
What is the general approach even in numerical solving of school
functions on the interval?
Can sage do that?
On Tuesday, May 5, 2015 at 9:53:22 PM UTC+3, Dima Pasechnik wrote:
This is an overtly optimistic point of view that find_root can solve
any
On Tue, May 5, 2015 at 6:58 PM, Jotace jotacebu...@gmail.com wrote:
I am trying to obtain the explicit expression for the solution od an ODE, my
code is
var('k')
y= function('y',x)
h=desolve(diff(y,x) - k*y*(1-y),y, ivar=x)
h
For this example you can do something like:
eq =
Thank you.
I have arbitrary system of equations.
I know, that find_root can solve any equation on interval.
Is there something similar to system of equations?
Your link didn't give answer.
On Tuesday, May 5, 2015 at 7:52:11 PM UTC+3, Alexander Lindsay wrote:
There's a good introduction on
