I'm not able to see sage like this:
[image: 20_VM_notebook.png]
I follow the instructions on http://wiki.sagemath.org/SageAppliance and get
this:
https://lh3.googleusercontent.com/-bIy36so8hXU/U20Ulq4fD-I/ABA/PSh--MHfMcU/s1600/Sage-6.png
And when i do Press *Right-Ctrl* and *F2* to
schreef Irene:
I have defined two extensions A1 and A2 over a finite field Fp2 with
generator b,
A1.theta=Fp2.extension(Ep)
A2.z=Fp2.extension(Q)
being Ep and Q polynomials.
Now I want to define a homomorphism between those algebras. I have
already computed alpha, that is the element in A2
,multiplicities=False)
it gives me a NotImplementedError. Any idea? Thank you in advance.
*Irene*
On Monday, April 21, 2014 3:52:53 PM UTC+2, John Cremona wrote:
On 21 April 2014 13:58, Irene irene@gmail.com javascript: wrote:
I forgot to write what is repsq():
You could use the builtin
is mapped, but Sage
doesn't allow me to define it as:
A1.hom([alpha], A2)
Do you know how to do it?
Irene
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root of theta^3+3*theta+5.*
*The problem is that when I consider the following:*
gamma2=theta^3+3*theta+5
AA1.xbar=PolynomialRing(A1)
AA.gamma=A1.extension(xbar^2-gamma2)
(xbar^2-gamma2).roots(AA,multiplicities=False)
it gives me a NotImplementedError. Any idea? Thank you in advance.
*Irene
, 2014 11:48:10 AM UTC+2, Irene wrote:
*Hello,*
*I have the following defined:*
p=371
Fp=GF(p)
E=EllipticCurve([Fp(3),Fp(5)])
j_inv=E.j_invariant()
l=13#Atkin prime
n=((l-1)/2).round()
r=2# Phi_13 factorize in factors of degree 2
s=12#Psi_13 factorize in factors of degree 12
Fps=GF
Hi!
I have the following:
p=371
Fp2=GF(p^2, 'b')
and I want to compute the cubic root of 344694*b + 1653339.
How can I do it? Because when I write (344694*b + 1653339)^(1/3) it gives
me as result 1, and the same for every element that I consider in Fp2, or
for every exponent 1/n.
--
You
Sorry, I didn't write it correctly. I meant GF(p^12,'a') instead of
GF(p^13,'a'). As 2 divides 12, GF(p^12,'a') is an extension of GF(p^2,'b').
My question is the same now with the correct data.
On Thursday, April 17, 2014 11:04:40 AM UTC+2, John Cremona wrote:
On 17 April 2014 01:55, Irene
what you want, I hope!
John
On 17 April 2014 02:52, Irene irene@gmail.com javascript: wrote:
Sorry, I didn't write it correctly. I meant GF(p^12,'a') instead of
GF(p^13,'a'). As 2 divides 12, GF(p^12,'a') is an extension of
GF(p^2,'b').
My question is the same now
, but I was using another version and I got many
problems and right now I don't have another option.
On Thursday, April 17, 2014 5:47:32 PM UTC+2, John Cremona wrote:
On 17 April 2014 08:43, Irene irene@gmail.com javascript: wrote:
I think that this is exactly what I need. Nevertheless I
)
and the result is
x^6 + (973912*b + 2535329)*x^5 + (416282*b + 3608920)*x^4 + (686636*b
+ 908282)*x^3 + (2100014*b + 2063451)*x^2 + (2563113*b + 751714)*x +
2687623*b + 1658379
On 17 April 2014 09:05, Irene irene@gmail.com javascript: wrote:
p=371
Fp=GF(p)
E=EllipticCurve([Fp(3),Fp
I am programming an example about elliptic curves but I need to define a couple
of field extensions to make there some operations and Sage consider them as
rings, then it doesn't allow me to compute divisions.
What can I do?
Here is the code:
p=371
Fp=GF(p)
E=EllipticCurve([Fp(3),Fp(5)])
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