hold( Dt(expression1) )
else:
return sum(map(lambda
arg:diff(expression1,arg)*Dt(arg),expression1.args()))
```
Apologies.
On 26/08/2024 00:06, erentar2002 wrote:
Thank you very much for your reply, i learned a lot
My initial intention when asking the prior question was to define
Thank you very much for your reply, i learned a lot
My initial intention when asking the prior question was to define a
function where some evaluations would return itself, while other
evaluations would not. Such as
```
def f(x):
if x%2==0:
return hold(f(x))
else:
retu
Greetings,
I am trying to return a function call from the function itself with the
context `hold`
The following example does not behave as i'd want:
```
def g(x):
with hold:
held = sqrt(x)
return held
g(4)
> 2
```
To get around this, i make the change SR(x):
```
def g(x):
My problem can be explained with the following two plots:
plot(factorial(x),x,0,9)
and
plot(factorial(x),x,0,10)
When plotting up to 9, the plot gives me exactly what i expect, a
linear-linear plot.
When plotting up to 10 though, sage silently chose to make the y-axis
log10. This should not
Hello! I hope the title was clear enough but here is my problem:
```
sage: var(x);
sage: solve( sin(x)==.5, x )
[x == 1/6*pi]
```
I believe this equation should have 2 solutions: `pi/6` and `5pi/6`.
What mistake did i do?
Thank you
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Thank you!
On 30/04/2022 09:09, Emmanuel Charpentier wrote:
Also :
|sage: b.simplify_trig() 1 |
Using specific simplifications in a specific order is often the key to
get interesting results that the brute-force |simplify_full| cannot.
Such simplifications are :
|sage: import re sage: pri
