Dears members, I trying to solve the next problem. Let be the chain of subspaces J1 \subset J2 \subset J3 \subset J4 over the finite field GF(3), where dim(J1) = 2, dim(J2) = 4, dim(J3) = 6 and dim(J4)=8. I want extract the basis vector of the subspace J4-J3, J3-J2 and J2-J1. For J4-J3 I get using the next code
K.<t> = GF(3) J3vectors = [[1,0,0,0,0,1,0,1],[0,1,0,0,0,1,0,0],[0,0,1,0,0,2,0,2],[0,0,0,1,0,0,0,2],[0,0,0,0,1,1,0,1],[0,0,0,0,0,0,1,1]] J3 = span(K,J3vectors) transpose(J3.basis_matrix()).kernel() But I don't know How I will be able to obtain J3-J2 and J2-J1, with J3, J2 . -- --------------------------------------------------------------------- MSc. Juan del Carmen Grados Vásquez Laboratório Nacional de Computação Científica Tel: +55 21 97633 3228 (http://www.lncc.br/) http://juaninf.blogspot.com --------------------------------------------------------------------- -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To post to this group, send email to sage-support@googlegroups.com. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
