b in QQ is (or should be) equivalent to QQ(b) not throwing an error. But if
that fails, it only means that Sage can't convert it to a rational directly,
it is perfectly possible that after a series of (computationally expensive)
steps one could transform b into a rational. But if we would
Hi Volker,
On 15 Sep., 11:45, Volker Braun vbraun.n...@gmail.com wrote:
b in QQ is (or should be) equivalent to QQ(b) not throwing an error.
No, that's incorrect. It should be (and is) equivalent to QQ(b)==b
returning True.
QQ(b) is just a conversion. You can convert any element of a finite
PS:
sage: cm.explain(QQ, b.parent())
I forgot to copy-and-paste the definition of cm. It was:
sage: from sage.structure.element import get_coercion_model
sage: cm = get_coercion_model()
Cheers,
Simon
--
To post to this group, send email to sage-support@googlegroups.com
To unsubscribe
Thank you to all of you!
On Sep 15, 12:59 pm, Simon King simon.k...@uni-jena.de wrote:
PS:
sage: cm.explain(QQ, b.parent())
I forgot to copy-and-paste the definition of cm. It was:
sage: from sage.structure.element import get_coercion_model
sage: cm = get_coercion_model()
