See also the answers to
http://ask.sagemath.org/question/10256/how-can-extract-different-terms-from-a-symbolic-expression/
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On Monday, March 9, 2015 at 3:49:01 PM UTC+1, projetmbc wrote:
>
> The string trick would do the job, but maybe the tree method would be
> nicer. How can I walk in the tree ? Is the tree the one of simply or
> another one ?
>
Any symbolic expression (part) has 0+ operators and 0+ operands.
See
The string trick would do the job, but maybe the tree method would be
nicer. How can I walk in the tree ? Is the tree the one of simply or
another one ?
*Christophe BAL*
*Enseignant de mathématiques en Lycée **et développeur Python amateur*
*---*
*French math teacher in a "Lycée" **and **Python *
slelievre:
projetmbc:
>
> suppose that I have *sqrt(6)*(sqrt(3)+5)*. How can I count
>>
> the number of square root in this expression ?
>>
>
> sage: a = sqrt(6)*(sqrt(3)+5)
> sage: a
> sqrt(6)*(sqrt(3) + 5)
> sage: s = str(a)
> sage: s
> 'sqrt(6)*(sqrt(3) + 5)'
> sage: s.count('sqrt')
> 2
>
or y
projetmbc:
suppose that I have *sqrt(6)*(sqrt(3)+5)*. How can I count
>
the number of square root in this expression ?
>
sage: a = sqrt(6)*(sqrt(3)+5)
sage: a
sqrt(6)*(sqrt(3) + 5)
sage: s = str(a)
sage: s
'sqrt(6)*(sqrt(3) + 5)'
sage: s.count('sqrt')
2
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