I have same difficulty of not finding roots, even for one simple
equation... :-)
R.=QQ[]
f1(x) = x^6 + x^5 + x^4 + x^3 + x^2 + x + 1
eqn = solve([f1 == 0],x)
print(eqn)
[
0 == x^6 + x^5 + x^4 + x^3 + x^2 + x + 1
]
while removing x^6:
R.=QQ[]
f1(x) = x^5 + x^4 + x^3 + x^2 + x + 1
eqn = s
I have same difficulty, even for one simple equation... :-)
2
R.=QQ[]
3
f1(x) = x^6 + x^5 + x^4 + x^3 + x^2 + x + 1
4
eqn = solve([f1 == 0],x)
5
print(eqn)
6
[
0 == x^6 + x^5 + x^4 + x^3 + x^2 + x + 1
]
while removing x^6:
R.=QQ[]
3
f1(x) = x^5 + x^4 + x^3 + x^2 + x + 1
4
eqn = sol
On 2014-05-28, George Hokke wrote:
> Hi,
> what I want to do is to solve an equation in which the function contains a
> numerical integral in its definition.
> Something like this:
>
> sage: d=lambda y: numerical_integral(x**2+y,0,1)[0]
> sage: d(0)
> 0.
>
> works until here.
> But no
Hello,
sage: A = matrix([[1, 0.106, 1.212], [3.8759765625, 0.04801171875,
: 3.972], [3.0625, 0.09325, 3.249]])
sage: A.rank()
3
sage: A.det()
0.000
Though sage computes the rank to be 3, the determinant is negligible.
Mathematica says the rank of this matrix is 2, and that its
det
> Thus (0,0,0) is the unique solution of your system.
Uh... not quite 'Thus'. The system in fact has an infinite number of
unique solutions, as the original poster pointed out. Though I don't
know why sage converges on [0,0,0]. Also just because a second sage
method gives the same result as the fi
