On 2013-01-14, Pierre Guillot wrote:
> partially answering my own question: for the "lame but easy method",
> one can do the following. Having a putative group H, try:
>
> for x in [g for g in G.Centre().Elements() if g.Order() == 2]:
> Q= G.FactorGroupNC( G.Subgroup([ x ]) ) # no idea wh
sorry G should be H throughout, in my last post.
2013/1/14 Pierre Guillot :
> partially answering my own question: for the "lame but easy method",
> one can do the following. Having a putative group H, try:
>
> for x in [g for g in G.Centre().Elements() if g.Order() == 2]:
> Q= G.FactorGroupNC
partially answering my own question: for the "lame but easy method",
one can do the following. Having a putative group H, try:
for x in [g for g in G.Centre().Elements() if g.Order() == 2]:
Q= G.FactorGroupNC( G.Subgroup([ x ]) ) # no idea why NC
if Q.IdGroup() == what you want
Thanks, I thought about this, but I'm not sure how to pick central elements
of order 2 in a group, or more precisely in a group that is given by
gap("SmallGroup(n,i)"). I can try C= G.centre() and then get C.generators()
but i'm not sure if I can assume anything about these generators (I doubt
Lame but easy method: Go though all groups with 2*G.Size() elements and
pick out the ones you want.
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