Thanks much, that helps and I am pretty sure I understand what is going on!
On Monday, March 24, 2014 10:49:18 AM UTC-4, Peter Bruin wrote:
>
> Hello,
>
> > I am working on a Z80 project and I needed 72 bits of precision for 64
> > elements of the form log2(1+2^-i) (so log2(3/2), log2(5/4),...)
Hello,
> I am working on a Z80 project and I needed 72 bits of precision for 64
> elements of the form log2(1+2^-i) (so log2(3/2), log2(5/4),...). I
> needed to convert these to hexadecimal, and it worked until I tried
> the following for i=56:
> int(256*log(1+2^-56,2))
>
> This returns 1, when in
