Hiya Burcin,
Thanks for reply!
For my cubic polynomials p0 and p1, I did get the following to work:
p0=p.series(x==xD[0],4)
p1=q.series(x==xD[1],4)
print p0; p1
x |--> 1.0601 + 0.59497*x +
(-0.08502)*x^3
x |--> 1.5698 + 0.34008*(x - 1)
On Thu, 10 Jan 2013 03:09:05 -0800 (PST)
LFS wrote:
> Hiya, Probably I am just doing something wrong ...
> I have a cubic polynomial p(x) with "regular" coefficients and I
> wanted coefficients around e.g. (x-1). So I did p1=p.taylor(x,1,3).
> I get:
>
> x |--> 0.085*(x - 1)^3 - 0.255*(x - 1)^2
Hiya, Probably I am just doing something wrong ...
I have a cubic polynomial p(x) with "regular" coefficients and I wanted
coefficients around e.g. (x-1). So I did p1=p.taylor(x,1,3).
I get:
x |--> 0.085*(x - 1)^3 - 0.255*(x - 1)^2 + 0.34*x + 1.23
The polynomial is correct, but look at the last
