On Tuesday, June 9, 2015 at 11:44:46 AM UTC-7, Nils Bruin wrote:
On Tuesday, June 9, 2015 at 10:05:26 AM UTC-7, Phoenix wrote:
@Lee Worden
Your code is deciding the linear independence of the set
{v,v*A,v*A^2,...,v*A^{dim(A)}}
That would always be linear dependent and not what the
@Lee Worden
Your code is deciding the linear independence of the set
{v,v*A,v*A^2,...,v*A^{dim(A)}}
But I want to decide the linear independence of the set {v,
A*v,..,,A^{dim(A)-1}*v}
On Fri, Jun 5, 2015 at 1:20 PM, Lee Worden worden@gmail.com wrote:
On Thursday, June 4, 2015 at
On Tuesday, June 9, 2015 at 10:05:26 AM UTC-7, Phoenix wrote:
@Lee Worden
Your code is deciding the linear independence of the set
{v,v*A,v*A^2,...,v*A^{dim(A)}}
That would always be linear dependent and not what the proposed code does
But I want to decide the linear independence of
[0] * i + [1] + [0] * (n-i-1)
On 05/06/15 00:11, Michael Orlitzky wrote:
On 06/04/2015 05:53 PM, Phoenix wrote:
Thanks!
Is there otherwise any standard operation in SAGE to create such vectors?
If the construction isn't too complicated, a list comprehension
usually suffices. This will do
On Thursday, June 4, 2015 at 2:53:50 PM UTC-7, Phoenix wrote:
Thanks!
Is there otherwise any standard operation in SAGE to create such vectors?
sage: def elem(i,n):
: return VectorSpace( QQ, n ).basis()[i]
:
sage: elem( 1, 5 )
(0, 1, 0, 0, 0)
or if you need it to return a
On Thursday, June 4, 2015 at 3:11:59 PM UTC-7, Michael Orlitzky wrote:
Given a vector $v$ and a matrix $A$ of dimension $n$, one would say that
$v$ is a cyclic vector of $A$ if the following set is linearly
independent
$\{ v,Av,A^2v,..,A^{n-1}v \}$.
Is there a way to test this
Use range(n-1) instead of range [n-1].
*Christophe BAL*
*Enseignant de mathématiques en Lycée **et développeur Python amateur*
*---*
*French math teacher in a Lycée **and **Python **amateur developer*
2015-06-04 23:44 GMT+02:00 Phoenix anirbit.mukher...@gmail.com:
I am trying to define a
Thanks!
Is there otherwise any standard operation in SAGE to create such vectors?
If you have time can you also look into another question I had about
vectors in SAGE:
Given a vector $v$ and a matrix $A$ of dimension $n$, one would say that
$v$ is a cyclic vector of $A$ if the following
On 06/04/2015 05:53 PM, Phoenix wrote:
Thanks!
Is there otherwise any standard operation in SAGE to create such vectors?
If the construction isn't too complicated, a list comprehension
usually suffices. This will do what you want, I think:
def elem(i,n):
return [ ZZ(i == j) for j
I am trying to define a function elem which will create me a list of
length n which has 1 at the i^th position.
def elem (i,n):
A = []
for k in range [n-1]:
if k != i:
A.append([0])
if k == i:
A.append([1])
return A
elem (1,5)
Why does the above not
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