sage: R.x,y=QQ[]
sage: f = R.random_element()
sage: g = R.random_element()
sage: f.resultant?
sage: f.resultant(g,x)
49/2*y^3 + 131/6*y^2 + 5/3*y + 1/3
sage: f.resultant(g,y)
-343*x^3 - 2285/36*x^2 - 253/18*x - 71/144
On 7 December 2013 06:34, 1982santu rsantum...@gmail.com wrote:
How one can
How one can find resultant of two bivariate polynomials in sage?
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I have two polynomials F(x,y,z) and G(x,y,z) over integer. From F, G I want
to eliminate z by resultant method. How can I do this?
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For
The following sage session shows a call to compute the resultant of
two polynomials that fails, and
another call that seems quite similar in syntax and semantics that
succeeds just fine. What's going on here? It seems to not
realize that f is a polynomial, since it says it's a
another failed attempt to compute a resultant, that doesn't involve
any quotient fields:
sage: R.z,p,e,d,f,g,h,r,l,m=QQ[]
sage: F = i*m*z^14 + (d+g)*z^13 + i*(f-p)*z^12 + e*z^11 + i*f*z^10 +
(e-g)*z^9 + i*(m+p)*z^8 + 2*d*z^7 - i*(m+p)*z^6 + (e-g)*z^5 -i*f*z^4 +
e*z^3 - i*(f-p)*z^2 + (d+g)*z - i*m
2010/1/31 Michael Beeson profbee...@gmail.com:
another failed attempt to compute a resultant, that doesn't involve
any quotient fields:
sage: R.z,p,e,d,f,g,h,r,l,m=QQ[]
sage: F = i*m*z^14 + (d+g)*z^13 + i*(f-p)*z^12 + e*z^11 + i*f*z^10 +
(e-g)*z^9 + i*(m+p)*z^8 + 2*d*z^7 - i*(m+p)*z^6 +
