Re: [scikit-learn] Bounded logistical regression in Python

I don't quite get your terminology, to "add a variable c to center an independent variable Xk", and you've got an extra ) in your equation, so I'm not sure exactly where you want it... If you mean P(X) = a / (1 + exp(b0 + b1*X1 + .. + bn*Xn) * (Xk - c)) then that's the same as P(X) = a / (1 + e

[scikit-learn] Bounded logistical regression in Python

Hi there! The standard logistical regression solver in scikit-learn assumes the regression equation: P(X) = 1/ (1 + exp(b0 + b1*X1 + ... + bn*Xn)) .. and solves for the b's using various solver routine