Re: CS>Mike M.'s process questions...

2003-06-20 Thread Mike Monett
url: http://escribe.com/health/thesilverlist/m60442.html Re: CS>Mike M.'s process questions... From: Robert Berger Date: Fri, 20 Jun 2003 06:26:38 > Mike D. > A #12 ga. wire is 0.0808" dia X 3.1416 x18 = 4.569 sq.in. > Need to take off sum for outside connection.

Re: CS>Mike M.'s process questions...

2003-06-20 Thread Robert Berger
Mike D. A #12 ga. wire is 0.0808" dia X 3.1416 x18 = 4.569 sq.in. Need to take off sum for outside connection. Why use silver for cathode? "Ole Bob" -- The silver-list is a moderated forum for discussion of colloidal silver. Instructions for unsubscribing may be found at: http://silverlist.

Re: CS>Mike M.'s process questions...

2003-06-19 Thread Mike Monett
url: http://escribe.com/health/thesilverlist/m60431.html Re: CS>Mike M.'s process questions... From: Mike Monett Date: Thu, 19 Jun 2003 22:40:16 Sorry, Mike. It rained last night and mold spores are everywhere. The headaches make it difficult to catch my mistakes before posting.

Re: CS>Mike M.'s process questions...

2003-06-19 Thread Mike Monett
url: http://escribe.com/health/thesilverlist/m60429.html CS>Mike M.'s process questions... From: M. G. Devour Date: Thu, 19 Jun 2003 19:18:34 >> Three feet of 12 ga wire cut in half should give about 3.8 square >> inches of wetted area for the anode and cathode. I run at

CS>Mike M.'s process questions...

2003-06-19 Thread M. G. Devour
> Three feet of 12 ga wire cut in half should give about 3.8 square > inches of wetted area for the anode and cathode. I run at 335 uA, so > the current density is around 87 uA/sq. in. Ummm, just to relieve me of digging out the calculator at this late hour... You're not counting the sur