CS>Re: Current limitation Please check my math

2003-04-29 Thread Mike Monett
CS>Re: Current limitation Please check my math From: Dave Sawatzky Date: Sun, 27 Apr 2003 20:17:53 Sorry, Dave, I forgot to mention another aspect of the shock hazard. You stated: > The purpose here is for greater shock protection in case of > polarity reversal. If y

CS>Re: Current limitation Please check my math

2003-04-29 Thread Mike Monett
Repost - sympatico hung when I tried to send. I don't think it went, but if so, I apologize for the duplicate post. ------- CS>Re: Current limitation Please check my math From: Dave Sawatzky Date: Sun, 27 Apr 2003 20:17:

CS>Re: Current limitation Please check my math

2003-04-27 Thread Dave Sawatzky
Hi Mike Monett You wrote > It sounds like the generator has a series resistor, but it's not > apparent what value is. The above numbers looked a bit strange, so I > tried to calculate it. >The first run of 6 hrs produced 24.5V and 3.24mA. The series > resistance calculates to:

Re: CS>Re: Re: CS>Re: Re: CS>RE: Current limitation Please check my math

2003-04-27 Thread Robert Berger
Thanks Mike, I've been bit a few times building my xmtrs!! I'll keep your post so I will remember. "Ole Bob" -- The silver-list is a moderated forum for discussion of colloidal silver. Instructions for unsubscribing may be found at: http://silverlist.org To post, address your message to: s

CS>Re: Re: CS>Re: Re: CS>RE: Current limitation Please check my math

2003-04-27 Thread Mike Monett
Hi Bob, > Re: CS>Re: Re: CS>RE: Current limitation Please check my math > From: Robert Berger > Date: Sat, 26 Apr 2003 17:39:26 > Hi Mike, > A clever solution to the problem of EIS power supplies. > I have a few 330 v c supplies here to check with m

Re: CS>RE: Current limitation Please check my math

2003-04-26 Thread Ode Coyote
First order of misperception is that...you can't see ions. What you are seeing is clouds of particles forming in two different places under somewhat different conditions where the dissolved ionic concentration in the container is the highest near the emmitting electrode and the attracting e

Re: CS>Re: Re: CS>RE: Current limitation Please check my math

2003-04-26 Thread Robert Berger
Hi Mike, A clever solution to the problem of EIS power supplies. I have a few 330 v c supplies here to check with my wide anode system. I believe that Trem is working on a system as a future sales item. I will look into the NO3 and NO levels. "Ole Bob" -- The silver-list is a moderated f

Re: CS>RE: Current limitation Please check my math

2003-04-26 Thread Mike Monett
Sorry, I goofed in my previous post on calculating the current density. Here's a better calculation: [...] > The anode calculates out to a little over 1 square inch: > A = pi * d * l > = pi * 0.125 * 3 > = 1.1780972 sq. in. That didn't sound right, so I looked up the actual w

CS>Re: Re: CS>RE: Current limitation Please check my math

2003-04-26 Thread Mike Monett
> Re: CS>RE: Current limitation Please check my math > From: Robert Berger > Date: Sat, 26 Apr 2003 09:27:03 > Hi Ed, > First let us correct some errors. [...] > None of the LM series will work over 36 volts. You will have to > find the drawing that

Re: CS>RE: Current limitation Please check my math

2003-04-26 Thread Harvey Norris
--- Robert Berger wrote: > Hi Ed, > > First let us correct some errors. > > The anode the positive electrode is the one that > supplies the silver . The > cathode can be anything as it will silver plate. In many cases I have seen colloid deposits flowing from both polarity sides on the CS proce

Re: CS>RE: Current limitation Please check my math

2003-04-26 Thread Robert Berger
Hi Ed, First let us correct some errors. The anode the positive electrode is the one that supplies the silver . The cathode can be anything as it will silver plate. #14 wire is 1/16" in diameter not 1/8" In the calculation you only use the area of the anode (+) electrode. make it large. None o

Re: CS>RE: Current limitation Please check my math

2003-04-25 Thread Jim
1/8 inch is .125" not .064. .064 = about 1/16 " Jim edkas...@pacbell wrote: Thanks Bob, if the silver wire is 14 gauge (14 gauge = 0.064") 14 gauge = about 1/8 of an inch the equalization would be 3.1416 x (0.064) x 7 (inches of wetted area) measured on only one of the two silver wires. eq

RE: CS>RE: Current limitation Please check my math

2003-04-25 Thread edkas...@pacbell
Thanks Bob, if the silver wire is 14 gauge (14 gauge = 0.064") 14 gauge = about 1/8 of an inch the equalization would be 3.1416 x (0.064) x 7 (inches of wetted area) measured on only one of the two silver wires. equals = 1.4070 ma if a bend the negative silver wire so there is 14 inches of we