Hi
I think that there is a way out!!
You can get an access to SOAPContext object at the server side. Now this
SOAPContext object has a getBaseUri() method! (See the API docs of Apache
SOAP)
I think that you can get an access to the URI of the client using this!
Regards,
Paramdeep
- Original
Hi,
With Apache SOAP, is it possible to get the URL from which client is calling
a function on the server? The reason I am asking is because I read something
about limitation of getting base URI from multiheader.
Thanks
Oleg
Hi
I want to write SOAP headers (custom) in the SOAP payload. On the client
side I think that this can be achieved using the Header class.
But I want to this at the server side! That is say I have a service called
SoapService. (SoapService.java) Now I want to read and write SOAP headers in
this
Run it through the tcptunnel and see what is actually going back and
forth.
cheesr
dim
On Mon, 10 Sep 2001 [EMAIL PROTECTED] wrote:
> Hi Minh/Dmitri and others,
> I have incorporated your suggestion.
> Unfortunately, i am not able to get this to work either :(
>
> Now, running the program does
Hi Minh/Dmitri and others,
I have incorporated your suggestion.
Unfortunately, i am not able to get this to work either :(
Now, running the program does not throw any exception.
I am printing the value of the result object at the end now.
What i get now is zero and not the correct result.
I have
beat me to it :)
On Monday 10 September 2001 15:44, you wrote:
You need to tell the call what type "AddResult" is. Have a look at
SOAPMappingRegistry.
cheesr
dim
On Mon, 10 Sep 2001 [EMAIL PROTECTED] wrote:
> Hi,
> I am trying to invoke a .Net enabled web service using Java with Apache
> SOAP
Hi Rahul,
The problem is the namespace in which the result of the service is defined.
If you map the result using the the SOAPMappingRegistry like so:
{
...
SOAPMappingRegistry smr = new SOAPMappingRegistry();
smr.mapTypes(Constants.NS_URI_SOAP_ENC, new
QName("http://lo
You need to tell the call what type "AddResult" is. Have a look at
SOAPMappingRegistry.
cheesr
dim
On Mon, 10 Sep 2001 [EMAIL PROTECTED] wrote:
> Hi,
> I am trying to invoke a .Net enabled web service using Java with Apache SOAP toolkit.
>
> I get the following exception:
> [SOAPException: fa
Hi,
I am trying to invoke a .Net enabled web service using Java with Apache SOAP toolkit.
I get the following exception:
[SOAPException: faultCode=SOAP-ENV:Client; msg=No Deserializer found to deserialize a
'http://localh
ost/:AddResult' using encoding style 'http://schemas.xmlsoap.org/soap/enco
> Hi,
> I have a doubt if SOAP supports in/out parameters. If yes then how do i
> accomplish that. I would like someone to go through my problem and give me
> clear solution. Thanks in advance. I have a method signature as follows "
> public void getAddress(Address objAddress)" . As you can see t
Hi,
I have a doubt if SOAP supports in/out parameters. If yes then how do i
accomplish that. I would like someone to go through my problem and give me
clear solution. Thanks in advance. I have a method signature as follows "
public void getAddress(Address objAddress)" . As you can see the return
Hi
Did you try setting the encoding style to:
call.setEncodingStyleURI(Constants.NS_URI_LITERAL_XML);
If you just pass the root Element of the document using this encoding it
will work. Nevermind I have already tried
converting a document to a string from a delphi client and it works fine
too.
In
I have the same problem :
SOAP-ENV:Server.BadTargetObjectURI
Unable to resolve target object: sg.RtfeServices
java.lang.ClassNotFoundException: sg.RtfeServices
at java.net.URLClassLoader$1.run(URLClassLoader.java:200)
at
The descriptor is ok, as been deployed ok, and is vis
"Ümit Yaman" wrote:
>
> William Brogden wrote:
>
> > I strongly suggest you put Catalog in a package. Tomcat gets confused
> > when a servlet tries to use a class not in a package.
>
> ok, I put my Catalog-class in a package called samples.catalogs.
>
> Now my Catalog.class is available in:
William Brogden wrote:
> I strongly suggest you put Catalog in a package. Tomcat gets confused
> when a servlet tries to use a class not in a package.
ok, I put my Catalog-class in a package called samples.catalogs.
Now my Catalog.class is available in:
C:\SOAP-2_2\samples\catalogs\Cat
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