Hello,
qry =
session.query(AssetCategory).join(Asset).join(Shot).filter(Shot.id==1).distinct()
this one already did the trick.
qry = qry.filter(Shot.id==shot_id_of_interest)
what did you add this for? The results seem to be identical...
that generates
SELECT DISTINCT AssetCategory.id
Ok so far I have this:
expressions = []
for tag in tag_list:
expressions += session.query(Document).filter(Tag.tag==tag)
documents =
session.query(Document).join(Document.tags).filter(and_(*expressions))
Doesn't work but it's progress! :)
On Mar 18, 2:37 pm, Stodge sto...@gmail.com
Now we're getting somewhere:
expressions = []
for tag in tag_list:
expressions += [Tag.tag==tag]
documents =
session.query(Document).join(Document.tags).filter(and_(*expressions))
Thanks to a Storm example I found. :)
On Mar 19, 8:12 am, Stodge sto...@gmail.com wrote:
Ok so far I have
select document.* from document join tags on document.id=tags.document_id
where tags.tag='foo' and tags.tag='bar' and tags.tag=
am I missing something ? that would return no rows in most cases.
if you want to find documents that have an exact list of tags, you'd have to do
something like
Thanks. That doesn't quite work. Based on my data, the following
should (and does) work because it only returns document id=1, which
only has these two tags:
tag_list = ['my document', 'source code']
session.query(Document).\
filter(Document.tags.any(Tag.tag.in_([t for t in tag_list]))).\
Getting closer. Maybe something like this:
q1 = session.query(Document).join(Document.tags).filter(Tag.tag=='my
document')
q2 =
session.query(Document).join(Document.tags).filter(Tag.tag=='source
code')
q3 = q1.intersect(q2)
q4 = session.query(Document).filter(Document.title=='Source Code')
print
Stodge wrote:
Thanks. That doesn't quite work. Based on my data, the following
should (and does) work because it only returns document id=1, which
only has these two tags:
tag_list = ['my document', 'source code']
session.query(Document).\
filter(Document.tags.any(Tag.tag.in_([t for t
Consider 3 tables A,B,C
A JOIN B ON A.id = B.id
produce all the columns required for an insert into C.
I can write:
C.insert().values(dict(zip(record.keys(), record.items()))
With use_labels == True and fold_equivalents == False the above
solution does not work
because the join columns labels
Opsss!
dict(zip(record.keys(), record.items())
must be
dict(record.items())
On 19 Mar, 16:23, marco vaccari agat...@gmail.com wrote:
Consider 3 tables A,B,C
A JOIN B ON A.id = B.id
produce all the columns required for an insert into C.
I can write:
With query() I can add with_lockmode('for update'). Can I do so on a
session.refresh()? What about a get()?
I see this as a useful approach to a two phase large query, where one
wants to avoid locking a large number of rows. First you would issue
a non-locking query and then, once you have a
Hi guys,
i am using SA 0.5.5.
Is it possible to specify the database engine while connecting t the
database.
i want to use INNODB for mysql, default is myisam
right now i am changing the storage engine in mysql conf file.
but this will be applied for the whole db.
i need only one db with innodb
On Mar 19, 2010, at 12:34 PM, Kent wrote:
With query() I can add with_lockmode('for update'). Can I do so on a
session.refresh()? What about a get()?
a get() yes. a refresh() no, but that's a fine idea so I've committed a flag
for that in rab5a31b4f3bf. A substitute is
On Mar 19, 2010, at 11:23 AM, marco vaccari wrote:
Consider 3 tables A,B,C
A JOIN B ON A.id = B.id
produce all the columns required for an insert into C.
I can write:
C.insert().values(dict(zip(record.keys(), record.items()))
With use_labels == True and fold_equivalents == False the
Thanks! That worked beautifully. :)
On Mar 19, 11:18 am, Conor conor.edward.da...@gmail.com wrote:
Stodge wrote:
Thanks. That doesn't quite work. Based on my data, the following
should (and does) work because it only returns document id=1, which
only has these two tags:
tag_list = ['my
By the way, must get() always accept a primary key? For composite
keys is there a shortcut to access its ident (in the correct
order)? (So I could get the ident tuple and pass it to get() with
populate_existing())
On Mar 19, 2010, at 1:12 PM, Michael Bayer mike...@zzzcomputing.com
obj._sa_instance_state.sort_key?? Will that always be sorted how
get() expects? Is there a more public way to get that?
On Mar 19, 1:42 pm, Kent Bower k...@retailarchitects.com wrote:
By the way, must get() always accept a primary key? For composite
keys is there a shortcut to access its
if you have an instance already, you're looking for
object_mapper(instance).primary_key_from_instance(instance).
On Mar 19, 2010, at 1:42 PM, Kent Bower wrote:
By the way, must get() always accept a primary key? For composite keys is
there a shortcut to access its ident (in the correct
I'm trying to refactor an existing cherypy/pyamf application and am running
into the following problem. The code:
@RemoteClass(alias=common.model.vo.OrderVO)
class OrderVO(object): pass
class Orders(Service):
Query and modify model.application.Order
klass = model.Order
@secure()
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