Thanks Michael Trier.
Michael Bayer,
Can you help me with the other two questions I asked ?
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I have packages and repos. A package can be in many different repos
and a repo has many packages. I want to have an additional
relationship to capture the 'status' of a particular package in a
particular repo. This would be a many-to-many relationship with an
additional field, so I guess I have to
-Original Message-
From: sqlalchemy@googlegroups.com [mailto:sqlalchemy@googlegroups.com]
On Behalf Of frankentux
Sent: 14 April 2011 14:42
To: sqlalchemy
Subject: [sqlalchemy] Create a one-to-many relationship using
association object with two foreign key primary keys
I have
Looks like you need to specify a composite ForeignKey
http://www.sqlalchemy.org/docs/core/schema.html?highlight=foreign_keys#sqlalchemy.schema.ForeignKeyConstraint
comment_table = Table('comment',metadata,
Column('id',Integer,primary_key=True),
Column('package_id', Integer),
On Apr 14, 2011, at 9:36 AM, bool wrote:
Thanks Michael Trier.
Michael Bayer,
Can you help me with the other two questions I asked ?
yes but I would note that lots of people on this list are capable of answering
these questions. Am trying to slow my responses so that others can
Thanks Michael! Re: the heavy get() workload, that's a neat trick :-)
Unfortunately for our workload, we don't really know which set of gets()
are going to fire, and we can't fit the entire table into memory.
I was curious about whether passing in fields instead of tables into Query
and
On Apr 14, 2011, at 5:07 PM, Chung wrote:
Thanks Michael! Re: the heavy get() workload, that's a neat trick :-)
Unfortunately for our workload, we don't really know which set of gets() are
going to fire, and we can't fit the entire table into memory.
I was curious about whether
Here's a quick example:
the query form i'm aiming for is:
select x - lag(x) over ( order by x ) from a;
meta=MetaData()
a = Table('a', meta, Column('x',Integer))
print select([ a.c.x , over( func.lag(a.c.x), order_by =
a.c.x ) ] ) # no problem
print select([ a.c.x - over(
On Apr 14, 2011, at 10:51 PM, botz wrote:
Here's a quick example:
the query form i'm aiming for is:
select x - lag(x) over ( order by x ) from a;
meta=MetaData()
a = Table('a', meta, Column('x',Integer))
print select([ a.c.x , over( func.lag(a.c.x), order_by =
a.c.x ) ] ) # no
On Apr 13, 2011, at 5:52 AM, Lars wrote:
Hi Michael,
I am trying to figure out the two suggestions you did, and not getting
very far. Some basic questions:
- if A, B, C are mapped classes, can you do A.join(B, A.id ==
B.id).join(C, B.id == C.id).join( ?
usually if you want to use
Great, thanks for the quick fix.
Found another minor bug with the window functions,
syntax should be
( partition by x order by y)
not
( partition by x, order by y)
... at least for postgresql.
On Apr 14, 8:51 pm, botz randa...@gmail.com wrote:
Here's a quick example:
the query form i'm
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