I receive this error:
This result object does not return rows. It has been closed automatically.
суббота, 27 января 2018 г., 1:09:53 UTC+3 пользователь Mike Bayer написал:
>
> On Fri, Jan 26, 2018 at 4:21 PM, Евгений Рымарев
> > wrote:
> > Hello, everyone!
>
написал:
>
> On Fri, Jan 26, 2018 at 4:21 PM, Евгений Рымарев
> > wrote:
> > Hello, everyone!
> > Engine:
> > engine = create_engine(
> >
> >
> 'mssql+pymssql://{LOGIN}:{PASSWORD}@{HOST}/{DATABASE}?charset={CHARSET}'.format(**D
Hello, everyone!
Engine:
engine = create_engine(
'mssql+pymssql://{LOGIN}:{PASSWORD}@{HOST}/{DATABASE}?charset={CHARSET}'.format(**DATABASE),
isolation_level='READ COMMITTED'
)
My first decorator for session:
@decorator_with_args
def session_decorator(func, default=None):
def wrapper(
Hello!
How i can create something like that:
SELECT column
INTO #tmptbl
FROM table
SELECT *
FROM table2 t2
WHERE EXISTS(SELECT 1
FROM #tmptbl
WHERE column = t2.column)
in SQLAlchemy I imagine it like this:
tmptbl = session.query(table.c.column).into('#tmptbl')
subqu1 = s
In SQLAlchemy code last string must be like this of course
result = session.query(table2).filter(subqu1)
суббота, 16 декабря 2017 г., 11:41:12 UTC+3 пользователь Евгений Рымарев
написал:
>
> Hello!
> How i can create something like that:
> SELECT column
> INTO #tmptbl
> FRO
Hello!
How i can create something like that:
SELECT column
INTO #tmptbl
FROM table
SELECT *
FROM table2 t2
WHERE EXISTS(SELECT 1
FROM #tmptbl
WHERE column = t2.column)
in SQLAlchemy I imagine it like this:
tmptbl = session.query(table.c.column).into('#tmptbl')
subqu1 = s
egies.py",
line 105, in connect
return dialect.connect(*cargs, **cparams)
File
"/usr/local/lib/python3.5/site-packages/sqlalchemy/engine/default.py", line
393, in connect
return self.dbapi.connect(*cargs, **cparams)
File "/usr/local/lib/python3.5/site-packages/fdb/fbc
quot;.
пятница, 3 марта 2017 г., 20:08:45 UTC+3 пользователь Евгений Рымарев
написал:
>
> Hello everyone!
> I have Flask app with using flask_sqlalchemy:
>
> from flask import Flask
> from flask_sqlalchemy import SQLAlchemy
> app = Flask(__name__)
> app.config.from_pyfile(fi
Hello everyone!
I have Flask app with using flask_sqlalchemy:
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
app = Flask(__name__)
app.config.from_pyfile(filename='settings.py', silent=True)
db = SQLAlchemy(app=app)
I want connect to same database from daemon. In daemon i just im
