I have a MySQL database with the following structure and was hoping someone could help me convert the SQL query below to SQLAlchemy.
*Database structure:* *bottom:* id name middle_id *middle:* id name top_id *top:* id name *Here are my models:* class Bottom(db.Model): id = db.Column(db.Integer, primary_key=True) name = db.Column(db.String(64)) middle_id = db.Column(db.Integer, db.ForeignKey('middle.id')) middle = db.relationship('Middle', backref=db.backref('bottoms', lazy='dynamic')) class Middle(db.Model): id = db.Column(db.Integer, primary_key=True) name = db.Column(db.String(64)) top_id = db.Column(db.Integer, db.ForeignKey('top.id')) top = db.relationship('Top', backref=db.backref('middles', lazy='dynamic')) class Top(db.Model): id = db.Column(db.Integer, primary_key=True) name = db.Column(db.String(64)) *Here's the SQL I want to convert to SQLAlchemy:* SELECT b.*, m.*, t.* FROM bottom AS b LEFT JOIN (SELECT id, name, top_id from middle) AS m on m.id = b.middle_id LEFT JOIN (SELECT id, name FROM top) AS t on t.id = m.top_id Thank you in advance :). -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To view this discussion on the web visit https://groups.google.com/d/msg/sqlalchemy/-/JpDLJzBXBzUJ. To post to this group, send email to sqlalchemy@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.