My question is about SQLAlchemy but I'm having troubles explaining it
in words so I figured I explain it with a simple example of what I'm
trying to achieve:
parent = Table('parent', metadata,
Column('parent_id', Integer, primary_key=True),
Column('name', Unicode),
)
parent_child = Table('parent_child', metadata,
Column('parent_id', Integer, primary_key=True),
Column('child_id', Integer, primary_key=True),
Column('number', Integer),
ForeignKeyConstraint(['parent_id'], ['parent.parent_id']),
ForeignKeyConstraint(['child_id'], ['child.child_id']),
)
child = Table('child', metadata,
Column('child_id', Integer, primary_key=True),
Column('name', Unicode),
)
class Parent(object):
pass
class ParentChild(object):
pass
class Child(object):
pass
>>> p = Parent(name=u'A')
>>> print p.children
{}
>>> p.children[0] = Child(name=u'Child A')
>>> p.children[10] = Child(name=u'Child B')
>>> p.children[10] = Child(name=u'Child C')
This code would create 3 rows in parent_child table, column number
would be 0 for the first row, and 10 for the second and third row.
>>> print p.children
{0: [<Child A>], 10: [<Child B>, <Child C>]}
>>> print p.children[10][0]
<Child B>
(I left out all SQLAlchemy session/engine code in the example to make
it as clean as possible)
I did a try using´
collection_class=attribute_mapped_collection('number')
on a relation between Parent and ParentChild, but it only gave me one
child for each number. Not a dict with lists in it.
Any help appreciated!
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"sqlalchemy" group.
To post to this group, send email to sqlalchemy@googlegroups.com
To unsubscribe from this group, send email to
sqlalchemy+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/sqlalchemy?hl=en
-~----------~----~----~----~------~----~------~--~---
