Dear all, I have the following query that is made of 3 queries on only ONE TABLE:
1. Step simple normal query somequery=session.query(tab.columns['name'],tab.columns['id']).filter(tab.columns['value']=="6") 2. Step: finding the max serial number for each serie maxquery=session.query(func.max(tab.columns['serial_number']),datab.columns['serie']).group_by(datab.columns['serie']) 3. Step: find name and id of each row satisfying query from Step1 having maximal serial number in a serie finalquery=somequery.filter(tuple_(tab.columns['serial_number'],datab.columns['serie']).in_(fidq)) Is there any more efficient way to do this? I am especially not thrilled with the step 3 (creating tuples and then searching equivalents from the results of the query 2). I think it is very cost- intensive. Remark: All rows with the same name and id also have the same serie attribute. Thanks -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.
