[sqlalchemy] Polymorphic forces table definition outside of declarative class?

2011-06-08 Thread Eric Ongerth
# Currently I have to do this: from sqlalchemy import Table, Column, Text, Integer Base = sqlahelper.get_base() sometable = Table('sometable', Base.metadata, Column('id', Integer, primary_key=True), Column('discriminator', Text), Column('data', Text)) class

Re: [sqlalchemy] Polymorphic forces table definition outside of declarative class?

2011-06-08 Thread Michael Bayer
On Jun 8, 2011, at 5:19 PM, Eric Ongerth wrote: # Meanwhile, the following way of doing it doesn't work. # But it seems like it would make sense and might be worth enabling. class SomeClass(Base): __table__ = Table('sometable', Base.metadata, Column('id', Integer,