On Mon, 13 Jul 2009 19:18:39 -0400
Michael Bayer mike...@zzzcomputing.com wrote:
Brad Wells wrote:
Is it possible to perform a query.count() on a query with a labeled
column expression without count() adding the subselect? I need to
filter on the value of the expression and get a count
Kyle Schaffrick wrote:
On Mon, 13 Jul 2009 19:18:39 -0400
Michael Bayer mike...@zzzcomputing.com wrote:
Brad Wells wrote:
Is it possible to perform a query.count() on a query with a labeled
column expression without count() adding the subselect? I need to
filter on the value of the
On Wed, 15 Jul 2009 10:35:24 -0400
Michael Bayer mike...@zzzcomputing.com wrote:
Kyle Schaffrick wrote:
On Mon, 13 Jul 2009 19:18:39 -0400
Michael Bayer mike...@zzzcomputing.com wrote:
Brad Wells wrote:
Is it possible to perform a query.count() on a query with a
labeled
On Jul 15, 2009, at 5:03 PM, Kyle Schaffrick wrote:
len(query) forces us to play games with the __iter__ method on query
such that it can't be a real iterator.
Hmm, I thought there was a __len__ magic method, such that
len(something) is the same as something.__len__(), when the latter is
Brad Wells wrote:
Is it possible to perform a query.count() on a query with a labeled
column expression without count() adding the subselect? I need to
filter on the value of the expression and get a count for a paged view.
use query.value(func.count(some column)).I'm seriously
Brad Wells wrote:
Is it possible to perform a query.count() on a query with a labeled
column expression without count() adding the subselect? I need to
filter on the value of the expression and get a count for a paged view.
although reading the docs to query.count(), its pretty clear as far
