On Sep 9, 9:53 am, Conor <conor.edward.da...@gmail.com> wrote:
> On 09/08/2010 01:05 PM, Jack Kordas wrote:
>
>
>
> > When I try to use both aliases and labels, the results are not named
> > as expected.
>
> > Instead of being able to access the columns as <label-name>_<column-
> > name> it appears as <original-table-name>_<numeric-sequence>_<column-
> > name>
>
> > Thanks,
> > Jack
>
> > Sample code follows:
>
> > parent = Table('parent', metadata,
> > Column('id', INTEGER(), primary_key=True),
> > Column('name', VARCHAR(length=128)),
> > Column('first_id', INTEGER(),
> > ForeignKey(u'child.id')),
> > )
>
> > child = Table('child', metadata,
> > Column('id', INTEGER(), primary_key=True),
> > Column('name', VARCHAR(length=128))
> > )
>
> > def test_labels1(conn):
> > s = select([parent,child], use_labels=True)
> > s = s.where(parent.c.first_id==child.c.id)
> > return conn.execute(s).fetchone()
>
> > def test_alias1(conn):
> > firstchild = child.alias()
> > s = select([parent,firstchild], use_labels=True)
> > s = s.where(parent.c.first_id==firstchild.c.id)
> > return conn.execute(s).fetchone()
>
> > conn = engine.connect()
>
> > results = test_labels1(conn)
> > print results.parent_name
> > print results.child_name
>
> > results = test_alias1(conn)
> > print 'alias1 results: '
> > print results.parent_name
> > #print results.firstchild_name # expected this to work
> > print results.child_1_name # this worked instead
>
> You need to set an explicit name for the alias to prevent SQLAlchemy
> from generating an anonymous name[1]:
>
> firstchild = child.alias("firstchild")
>
> -Conor
>
> [1]http://www.sqlalchemy.org/docs/core/expression_api.html#sqlalchemy.sq...
Thanks, that did the trick. I didn't appreciate the difference
between using the aliased variable in the from clause and generating
names for the selected columns.
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