This worked after using func() to pass currval and making literal
escaped single-quotes, like this: func.currval('users_user_id'). Thank
you everyone for the help.
On Mon, Feb 16, 2009 at 11:58 PM, jo jose.soa...@sferacarta.com wrote:
You cannot pass currval('users_user_id_seq') as a parameter
use func.currval(literal_column('users_user_id_seq')).though I'm
not sure how SQLSoup is going to pass that in, its what *should* work.
On Feb 16, 2009, at 7:03 PM, Jeff Cook wrote:
Hi all,
I want to use the return value of a CURRVAL call as the value of a
column in a row I'm
You cannot pass currval('users_user_id_seq') as a parameter value, you
have to pass an integer value instead.
I solved this problem in this way:
INSERT INTO employees
(employee_user_id, employee_id, employee_first_name,
employee_last_name, employee_address, employee_city, employee_state,
