On Nov 13, 2007, at 5:17 PM, Andrew Stromnov wrote:
> > I have this SQL expression (from > http://www.pui.ch/phred/archives/2005/04/tags-database-schemas.html) > > SELECT b.* > FROM tagmap bt, bookmark b, tag t > WHERE bt.tag_id = t.tag_id > AND (t.name IN ('bookmark', 'webservice', 'semweb')) > AND b.id = bt.bookmark_id > GROUP BY b.id > HAVING COUNT( b.id )=3 > > How to implement this "HAVING COUNT(b.id) = 3" in ORM? > upgrade to trunk revision 3769. use the having() method on Query in conjunction with group_by(). However, that query doesnt seem correct to me; it will fail in Postgres because the GROUP BY clause is invalid - it needs to name each column in the columns clause of the select (i.e. everything in b.*) that is *not* part of the aggregate criterion in having(). --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
