Thanks for this response. I do need all of the data available at once.
Specifically, here is what I'm trying to do. I'm following this
example right from the docs:
from sqlalchemy import ForeignKey
from sqlalchemy.orm import relation, backref
class Address(Base):
... __tablename__ =
Don't know if this will work in your case.. but to handle joins to so
many static tables.
Note.. I didn't need to update these tables, nor query from them back
to the data tables. (i.e. no need to call Gender.member_profiles())
I did something like the following:
class MemberProfile(Base):
Excellent, thank you! Getting closer. I now use the same
declarative_base on all instances, and I can now successfully refer to
the relation() classes as actual class names instead of strings.
During this query:
memberProfile = session.query(MemberProfile).filter_by
(memberID=81017).first()
I
Just to make it easier to read, I'm missing a FROM clause:
sqlalchemy.exc.ProgrammingError: (ProgrammingError) missing FROM-
clause entry for table member_profiles at character 5151
I read from the archive that this was a bug in 0.4.
Thanks again,
Gloria
so u have a member, pointing to member_profile, pointing to all its
attributes into separate tables?
one way IMO is to map all other 50 tables into simple classes, then
have member profile reference each of them, i.e. relation( ..
uselist=False). Then, if u need all of them at once, request a
