Option 2 works great. Thanks very much for your incredible support.
On Jan 7, 3:13 pm, Michael Bayer wrote:
> two choices. join explicitly:
>
> query(Event).join(Event.message).filter(Message.text.match(x))
>
> or use has() which produces an EXISTS subquery:
>
> query(Event).filter(Event.messag
two choices. join explicitly:
query(Event).join(Event.message).filter(Message.text.match(x))
or use has() which produces an EXISTS subquery:
query(Event).filter(Event.message.has(Message.text.match(x))
On Jan 7, 2009, at 1:23 PM, sol wrote:
>
> Using SA 0.5, sqlite, say I have the following
