On Sep 17, 2008, at 9:19 AM, Mark Mitchell wrote:
The code to replicate this exception is pretty simple:
count = con.scalar(select(['count(*)'], from_obj=my_table,
whereclause=text('mytable.column
like \'%\''))
That is my error, here is my
Thanks! That is good to know. Having trouble finding the docs for
psycopg2 -- any idea off the top of your head what the escape syntax
is for %? (When I put in '%%', pyscopg2 outputted %%, not %, to
postgres (but didn't throw the exception)).
I found the home page for pyscopg2 but no docs.
