if the database you're using doesn't support UPDATE..FROM (which is likely),
the normal way is to UPDATE with a subquery, which may be correlated or in a
simple case like this just using IN:
UPDATE price SET extra=2 WHERE price.id in (select price_id from person
where name like 'J%')
On Jun 18, 2013, at 4:46 PM, Witold Greń witold.g...@gmail.com wrote:
But how resolved no 5?
I try:
subq = session.query(Person).filter(Person.gender == False,
Person.name.like('M%')).subquery()
y = session.query(Projects).filter(Projects.students.any(subq)).count()
any() does the
Hi, I'm Witold and learn Sqlalchemy :)
I have a little problem, here it is:
This is my DB:
class Addressess(Base):
__tablename__ = 'addressess'
id = Column('id', Integer, Sequence('address_id_seq'),
primary_key=True, index=True, unique=True, nullable=False)
street =
I have a tested update ... from.. statement, like so:
update distributors set lead_bonus = lead_bonus + a.sum_amt
from (
select target_member as id, sum(amount) as sum_amt
from bonus_gen_history
where bonus_type=2 and sub_type=1 and source_member in
(select
On Sep 12, 2011, at 5:50 PM, Geo wrote:
I have a tested update ... from.. statement, like so:
UPDATE...FROM syntax, which is non-standard, isn't built into SQLAlchemy right
now. You'd need to either convert this to use a correlated SELECT in the
WHERE clause, stick to the SQL string, or
Thanks Michael, that solves my problem.
On Mon, Sep 12, 2011 at 3:18 PM, Michael Bayer mike...@zzzcomputing.comwrote:
On Sep 12, 2011, at 5:50 PM, Geo wrote:
I have a tested update ... from.. statement, like so:
UPDATE...FROM syntax, which is non-standard, isn't built into SQLAlchemy
