Does something like this work?
query = db.session.query(PostsModel).join(pn, PostsModel.id ==
pn.c.post_id).filter(pn.c.pn_nodes == db.session.query(n.c.n_nodes))
I can't help feeling this is a very inefficient query though. I still
don't really understand your data model (I don't understand
Okay, I have ORMed my sql statement:
pn = db.session.query(PNModel.post_id,
db.func.array_agg(PNModel.node_id.distinct()).label('pn_nodes')).group_by(PNModel.post_id)
n =
db.session.query(db.func.array_agg(NodesModel.id.distinct()).label('n_nodes')).filter(NodesModel.project_uuid
==
Hi Simon,
Sorry I think I really didn't make what I'm asking for clear.
I have these codes
nodes =
NodesModel.find_by_project_uuid_and_topic_list(project_uuid=project_uuid,
topic_list=node_dict['topics'])
node_id_list = [node.id for node in nodes]
select_sql = text('WITH pn_o AS (SELECT
I'm still not sure I understand. Here's an example that does what I
*think* you're asking for:
import sqlalchemy as sa
import sqlalchemy.orm as saorm
from sqlalchemy.ext.declarative import declarative_base
Base = declarative_base()
pn = sa.Table(
"pn", Base.metadata,
Hi Simon,
The tables and sample data are below.
So first I search the nodes table for a and b, getting the node_id of them
(in this example, 1 and 2).
Then using the SQL statement, I would get all posts that have 1 and 2 as
the node_id. So in the example data, 100, 103, 108 will be returned as
Hi Desmond.
I don't really understand your table structure. Could you present it
in the form of a standalone script that we can run (including sample
data)?
Thanks,
Simon
On Mon, Jun 10, 2019 at 2:57 AM Desmond Lim wrote:
>
> Hi there,
>
> I really have no idea how to do this via sqlalchemy.
