At 11:36 AM 1/31/2004 -0600, Kurt Welgehausen wrote:
You'll have to encrypt each column independently. If you use
the same key and initialization vector, you should be able to
search, but of course, only for exact matches. Also, the size
of each field will probably grow to the next multiple of
You'll have to encrypt each column independently. If you use
the same key and initialization vector, you should be able to
search, but of course, only for exact matches. Also, the size
of each field will probably grow to the next multiple of your
cipher's block size, so you'll need to pad the
2 matches
Mail list logo