@igor, @jay (and a good assist from @samuel):
Cool beans -- that works and is cleaner than my hack. Thank you.
FYA, the final form of this query (to be used as a sub-query throughout much
of our system) is:
> SELECT DATE('#{start_time.to_s(:db)}', (thousands.digit * 1000 +
>
Meh. I have a solution, but I don't like it very much because it feels
convoluted:
> sqlite> select strftime('%Y-%m-%d', julianday('2011-01-01') + digit) as d
> from digits;
> 2011-01-01
> 2011-01-02
> 2011-01-03
> 2011-01-04
> 2011-01-05
> 2011-01-06
> 2011-01-07
> 2011-01-08
> 2011-01-09
>
Samuel Adam-2 wrote:
>
>
> http://www.sqlite.org/lang_datefunc.html
> http://www.sqlite.org/lang_select.html
> (and a few others)
> Very truly,
>
Hi SA:
So I've been reading those very pages carefully. And since the docs say
> Note that "±NNN months" works by rendering the original date
I'd like to write a query that generates ten consecutive days starting at
"2011-02-05" (for example), but I believe I'm having trouble with quoting.
Assume I have a table of ten digits such as:
CREATE TABLE "digits" ("id" INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL,
"digit" integer)
INSERT INTO
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