On 2016-03-13 23:14, jungle Boogie wrote:
> Hi Keith,
> On 13 March 2016 at 13:31, Keith Medcalf wrote:
>> On Sunday, 13 March, 2016 13:36 -07:00, jungle Boogie > gmail.com> wrote:
>>> Here it is in decimal: (select code from sidemeters)
>>> "0"
>>> "1"
>>> "2"
>>> "5"
>>> "6"
>>> "7"
>>> "28"
Hi Keith,
On 13 March 2016 at 13:31, Keith Medcalf wrote:
> On Sunday, 13 March, 2016 13:36 -07:00, jungle Boogie gmail.com> wrote:
>> Here it is in decimal: (select code from sidemeters)
>> "0"
>> "1"
>> "2"
>> "5"
>> "6"
>> "7"
>> "28"
>> "29"
>> "30"
>> "31"
>
> Assuming that your quotes mean
On Sunday, 13 March, 2016 13:36 -07:00, jungle Boogie wrote:
> On 12 March 2016 at 22:07, J Decker wrote:
> > maybe ?
> > https://www.sqlite.org/lang_corefunc.html
> > hex(X)The hex() function interprets its argument as a BLOB and returns
> > a string which is the upper-case hexadecimal
On 12 March 2016 at 22:07, J Decker wrote:
> maybe ?
> https://www.sqlite.org/lang_corefunc.html
>
> hex(X)The hex() function interprets its argument as a BLOB and returns
> a string which is the upper-case hexadecimal rendering of the content
> of that blob.
That's what I first tried but not
maybe ?
https://www.sqlite.org/lang_corefunc.html
hex(X)The hex() function interprets its argument as a BLOB and returns
a string which is the upper-case hexadecimal rendering of the content
of that blob.
On Sat, Mar 12, 2016 at 12:18 PM, jungle Boogie
wrote:
> Hello All,
>
> I'm curious to
Hello All,
I'm curious to know if there's a better way to run a query and convert
the results to hexadecimal.
This is what I have so far:
SELECT printf("%x %d",code,code), printf("%x", denom) FROM sidemeters
order by denom
The data is already in decimal so I don't necessarily need to include
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