Michael Redler wrote: >Does anyone remember the equations for angular momentum and kinetic energy >from a rotating flywheel?
kinetic energy E = I * <omega>^2 /2 I for the homogeneous discus is I = m * R^2 / 2 <omega> is angular speed and can be calculated from <omega>= 2 * pi * <niu> where <niu> is revolutions per second or <niu> = RPM/60 angular momentum = I * <omega> these formulas for rotating motion are very easily derived from formulas for linear motion just replace mass m with inertia I, and speed v with angulav speed <omega> so from E=m*v^2/2 we can derive E= I*<omega>^2/2 from P = m*v we derive angular momentum = I * <omega> (i forget what letter is usualy used for angular momentum) The inertia I depends on object shape and is usually (for simple shapes) in the form I = m * r^2 * <some coefficient> for a very fine wall cilynder, coefficient is 1, for discus its 1/2, i forget what it is for sphere, 3/4?. You can derive these coefficients by doing integral of r^2 * delta m where r is the disstance from spin axis. hope this helps -- Tomas Juknevicius _______________________________________________ Biofuel mailing list Biofuel@sustainablelists.org http://sustainablelists.org/mailman/listinfo/biofuel_sustainablelists.org Biofuel at Journey to Forever: http://journeytoforever.org/biofuel.html Search the combined Biofuel and Biofuels-biz list archives (50,000 messages): http://www.mail-archive.com/biofuel@sustainablelists.org/
