On Sun, 2/5/17, alex.rhomb...@temet.ch wrote:
Subject: Re: How to override pattern from java @Pattern validation
To: "Swagger"
Date: Sunday, February 5, 2017, 1:08 AM
Thanks, I
did: https://github.com/swagger-api/swagger-core/i
Thanks, I did: https://github.com/swagger-api/swagger-core/issues/2102
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I think this is because of differences between Java and the REGEX format
supported in the editor. Could you please open an issue in swagger-core so we
can see about converting the syntax to the spec supported one?
> On Feb 4, 2017, at 2:52 PM, alex.rhomb...@temet.ch wrote:
>
> Relevant part in
Relevant part in yaml:
properties:
id:
type: integer
format: int64
name:
type: string
pattern: '(?U)\w[\w -]*\w'
Results in Swagger error Object didn't pass validation for format regex:
(?U)\w[\w -]*\w
If I remove the (?U) in swagger editor, the
Can you please share what is being emitted in the swagger definition?
> On Feb 4, 2017, at 12:15 AM, alex.rhomb...@temet.ch wrote:
>
> I have this validation:
>
> /**
> * @return the name
> */
> @NotNull
> //Validation:
> @Pattern(regexp="(?U)\\w[\\w -]*\\w")
> public final String getNam
I have this validation:
/**
* @return the name
*/
@NotNull
//Validation:
@Pattern(regexp="(?U)\\w[\\w -]*\\w")
public final String getName() {
return name;
}
The @Pattern is converted to a pattern constraint in swagger, but the (?U)
switch is not supported.
How can I override the pat
