(){
$this-getObject()-getRelatedObjectForm
On Oct 5, 11:20 pm, Francisco José Núñez Rivera elfra...@gmail.com
wrote:
I tried it with
$opinion = new Opinion();
$opfeat = new $opinion-OpinionFeature;
but cant find the class OpinionFeature...
Otherwise i do the same
DezignForDatabases. The guy who makes it is
very helpful and friendly. It's not perfect, but it's great for the
price.
On Oct 2, 3:39 am, Francisco José Núñez Rivera elfra...@gmail.com
wrote:
But all the opinions have the same features.
Feature - id , desc
1,Feature 1
But all the opinions have the same features.
Feature - id , desc
1,Feature 1 ; 2, Feature2...
Opinion shows all the features..
Feature 1 -Score:
Feature 2 - Score:
OpinionFeature - opinion_id , feature_id , score
I only insert a row here when im scoring a feature.
I think my schema is right...
