Status: Accepted
Owner:
Labels: Type-Defect Priority-Medium Integration
New issue 1426 by Vinzent.Steinberg: failing integral
http://code.google.com/p/sympy/issues/detail?id=1426
e=(x**m * (1 - x)**n * (a + b*x + c*x**2))/(1 + x**2)
e
x**m*(1 - x)**n*(a + b*x + c*x**2)/(1 + x**2)
Comment #6 on issue 1385 by Vinzent.Steinberg: Integral.midpoint()
implemented
http://code.google.com/p/sympy/issues/detail?id=1385
So maybe rather middle_sum(). How about calling it riemann_sum()
I'd prefer the first, I did not know that it's also Riemann sum. Maybe you
could even
omit
Status: Accepted
Owner:
Labels: Type-Defect Priority-High Milestone-Release0.6.5 WrongResult
New issue 1427 by ondrej.certik: subs for sqrt(a/b) is wrong
http://code.google.com/p/sympy/issues/detail?id=1427
In [4]: var(a b)
Out[4]: (a, b)
In [5]: e = sqrt(a/b)
In [6]: e
Out[6]:
Comment #1 on issue 1427 by tetaberta: subs for sqrt(a/b) is wrong
http://code.google.com/p/sympy/issues/detail?id=1427
As Sebastian pointed out, the problem is in expanding the sqrt()
In[8]:sympy.sqrt(a*b)
Out[8]: a**(1/2)*b**(1/2)
this has already been reported in issue #896
--
You received
Updates:
Status: Started
Comment #8 on issue 1385 by Vinzent.Steinberg: Integral.midpoint()
implemented
http://code.google.com/p/sympy/issues/detail?id=1385
Correct me if I'm wrong, but I think rectangle rule is an approximation
using
piecewise constant functions, trapez rule is an
Comment #9 on issue 1385 by ondrej.certik: Integral.midpoint() implemented
http://code.google.com/p/sympy/issues/detail?id=1385
Ok, that sounds reasonable. So we can call it approximation, and the method
will be
on of those (when all of them are implemented):
upper, lower, left, right,
Updates:
Status: Fixed
Comment #1 on issue 1317 by asmeurer: Wild/match does not discard x
correctly
http://code.google.com/p/sympy/issues/detail?id=1317
You forgot to put in what eq is. I am guessing from the match that it is
f(x).diff(x,x)+diff(f(x),x)/x+f(x), in which
case, the
suprising things indeed !
I get the same behavior with any rational power so the same rule seem
to be used with any kind of exponent.
Pablo
On 20 mai, 14:15, Sebastian basti...@gmail.com wrote:
The problem seems to be the following:
In[8]:sympy.sqrt(a*b)
Out[8]: a**(1/2)*b**(1/2)
With the
Last night I was deriving the moment of inertia for a solid torus
using Sympy. It mostly worked, except for the step where the
determinant of the Jacobian for the change of variables mapping was to
be computed, the result was unable to be simplified by trigsimp. I
gave it a shot anyway, and it
Luke wrote:
Last night I was deriving the moment of inertia for a solid torus
using Sympy. It mostly worked, except for the step where the
determinant of the Jacobian for the change of variables mapping was to
be computed, the result was unable to be simplified by trigsimp. I
gave it a
On Wed, May 20, 2009 at 7:29 AM, Luke hazelnu...@gmail.com wrote:
Last night I was deriving the moment of inertia for a solid torus
using Sympy. It mostly worked, except for the step where the
determinant of the Jacobian for the change of variables mapping was to
be computed, the result
On Wed, May 20, 2009 at 13:55, Ondrej Certik ond...@certik.cz wrote:
Hi Pablo!
On Wed, May 20, 2009 at 4:40 AM, Pablo W. pablo.win...@gmail.com wrote:
Hello,
I have been using sympy a lot recently (economical modelling) and
(while it's a great software) I found a strange behavior when
On 16 Mai, 23:33, Fredrik Johansson fredrik.johans...@gmail.com
wrote:
On Sat, May 16, 2009 at 1:29 PM, Ondrej Certik ond...@certik.cz wrote:
On Sat, May 16, 2009 at 1:00 PM, Aaron S. Meurer asmeu...@gmail.com wrote:
Maple also uses BesselJ, and I couldn't find a spherical function in
Ühel kenal päeval, K, 2009-05-20 kell 19:21, kirjutas Robert Kern:
On Wed, May 20, 2009 at 19:08, Luke hazelnu...@gmail.com wrote:
How can I most quickly determine the filename and path that a specific
sympy function lives in? For example, if I
from sympy import trigsimp
With any
I wrote a function for dsolve that is very complex and should be well
tested, but it is also very specialized (making it more modular would
require much more work), so I don't necessarily want it showing up in
isympy. Is there a way to access the function from the test without
putting it
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